SQL

Keep assets with no loose findings

BOTIE

Build the filtered left join before grouping. Find the null visit identity on an asset with no qualifying partner.
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Context for this challenge

Build the filtered left join before grouping. Find the null visit identity on an asset with no qualifying partner.

The supervisor needs a count for every registered asset, including those with no qualifying visits.

Inspect the component calculation
Match rows on a key(
  Left rows: Asset register
  Right rows: Keep rows passing a comparison(
    Rows: Inspection visits
    Comparison value: Text comparison value(
      Text: loose
    )
    Field to compare: finding
    Comparison: =
  )
  Left match field: asset_id
  Right match field: asset_id
  Join: left
  Right fields to carry: inspection_id
  Prefix for right fields: visit_
)
Examples and results
Asset register
[
  {
    "asset_id": "P1",
    "site": "north",
    "kind": "pump"
  },
  {
    "asset_id": "P2",
    "site": "north",
    "kind": "fan"
  },
  {
    "asset_id": "P3",
    "site": "south",
    "kind": "pump"
  },
  {
    "asset_id": "P4",
    "site": "south",
    "kind": "pump"
  }
]
Inspection visits
[
  {
    "inspection_id": 101,
    "asset_id": "P1",
    "minutes": 30,
    "finding": "loose"
  },
  {
    "inspection_id": 102,
    "asset_id": "P1",
    "minutes": null,
    "finding": null
  },
  {
    "inspection_id": 103,
    "asset_id": "P2",
    "minutes": 0,
    "finding": "clear"
  },
  {
    "inspection_id": 104,
    "asset_id": "P3",
    "minutes": 20,
    "finding": "clear"
  },
  {
    "inspection_id": 105,
    "asset_id": "P2",
    "minutes": 10,
    "finding": "loose"
  },
  {
    "inspection_id": 106,
    "asset_id": "P1",
    "minutes": 15,
    "finding": "loose"
  }
]
Required result
[
  {
    "asset_id": "P1",
    "site": "north",
    "kind": "pump",
    "visit_inspection_id": 101
  },
  {
    "asset_id": "P1",
    "site": "north",
    "kind": "pump",
    "visit_inspection_id": 106
  },
  {
    "asset_id": "P2",
    "site": "north",
    "kind": "fan",
    "visit_inspection_id": 105
  },
  {
    "asset_id": "P3",
    "site": "south",
    "kind": "pump",
    "visit_inspection_id": null
  },
  {
    "asset_id": "P4",
    "site": "south",
    "kind": "pump",
    "visit_inspection_id": null
  }
]
Try a fresh construction

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Stuck? Inspect a worked construction

The tools below form one possible solution. You can assemble it, follow its signals, and undo that change to return to your own construction.

Assumptions and test precision

The workshop calculates over small record lists to make the relational operations visible. It is not a SQL parser or query planner. The worksheet runs SQLite and is the authority for SQL behaviour, including types and NULL. Numerical tests allow a difference of 0.001. Lists and structures must also have the right shape.

Your last tested pieces can start the full construction. An existing draft there keeps its own pieces.

A real qualifying visit has no recorded minutes

This check uses the pieces from “Keep the register while counting qualifying visits”.

BOTIE

P8 has a loose visit with a real inspection ID and missing minutes; P9 has no visits. Predict the loose-visit counts.
Asset register
[
  {
    "asset_id": "P8"
  },
  {
    "asset_id": "P9"
  }
]
Inspection visits
[
  {
    "inspection_id": 8,
    "asset_id": "P8",
    "finding": "loose",
    "minutes": null
  }
]

Use a number, text, or an array matching the requested result. For a matrix, put each row in brackets. Saving your prediction runs your current construction on these inputs and checks the earlier examples too.

Build a construction in the workspace above first. This case will test those pieces.

Why should the group key come from the left asset register rather than the nullable right side?

Preserve the identity of the population the report promises to include.

The workshop calculates over small record lists to make the relational operations visible. It is not a SQL parser or query planner. The worksheet runs SQLite and is the authority for SQL behaviour, including types and NULL.

Work through the SQL challenges →
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